Given an array

`nums`

, write a function to move all `0`

's to the end of it while maintaining the relative order of the non-zero elements.
For example, given

`nums = [0, 1, 0, 3, 12]`

, after calling your function, `nums`

should be `[1, 3, 12, 0, 0]`

.
Note:

- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.

**Understand the problem:**

Since the problem requires to maintain the relative order of the array, we cannot simply swap the numbers in the array.

One simple way is very similar to remove the duplicated numbers in the array. In the first pass, we move all the non-zero elements upfront and fill out all the zero slots. Then we just need to append 0s at the end of the array.

**Code (Java):**

public class Solution { public void moveZeroes(int[] nums) { if (nums == null || nums.length == 0) { return; } int i = 0; int j = 0; // Step 1: compress the nums array by filling out the 0s while (i < nums.length) { if (nums[i] != 0) { nums[j] = nums[i]; j++; i++; } else { i++; } } // Append 0s to the end while (j < nums.length) { nums[j] = 0; j++; } } }

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