International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:
"a"maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on.
For convenience, the full table for the 26 letters of the English alphabet is given below:
[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cba" can be written as "-.-..--...", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.
Return the number of different transformations among all words we have.
Example: Input: words = ["gin", "zen", "gig", "msg"] Output: 2 Explanation: The transformation of each word is: "gin" -> "--...-." "zen" -> "--...-." "gig" -> "--...--." "msg" -> "--...--." There are 2 different transformations, "--...-." and "--...--.".
Note:
- The length of
wordswill be at most100. - Each
words[i]will have length in range[1, 12]. words[i]will only consist of lowercase letters.
class Solution {
private String[] morseCodes = new String[]{
".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};
public int uniqueMorseRepresentations(String[] words) {
if (words == null || words.length == 0) {
return 0;
}
Set<Integer> set = new HashSet<>();
int ans = 0;
for (String word : words) {
int code = getHashValue(word);
if (!set.contains(code)) {
ans++;
set.add(code);
}
}
return ans;
}
private int getHashValue(String s) {
int ans = 0;
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
sb.append(morseCodes[s.charAt(i) - 'a']);
}
ans = morseToNumber(sb.toString());
return ans;
}
private int morseToNumber(String s) {
int ans = 0;
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
ans = ans * 2 + (c == '-' ? 1 : 0);
}
return ans;
}
}
No comments:
Post a Comment