Given a string s, find the longest palindromic subsequence's length in s. You may assume that the maximum length of s is 1000.
Example 1:
Input:
Input:
"bbbab"Output:
4One possible longest palindromic subsequence is "bbbb".
Example 2:
Input:
Input:
"cbbd"Output:
2One possible longest palindromic subsequence is "bb".
Analysis:
The problem is similar to the longest palindromic substring. So we use dp[i][j] means from character i to j, the longest palindromic substring.
Code (Java):
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 | class Solution { public int longestPalindromeSubseq(String s) { if (s == null || s.length() == 0 ) { return 0 ; } int [][] dp = new int [s.length()][s.length()]; int maxLen = 0 ; for ( int i = s.length() - 1 ; i >= 0 ; i--) { for ( int j = i; j < s.length(); j++) { if (s.charAt(i) == s.charAt(j)) { if (j - i < 2 ) { dp[i][j] = j - i + 1 ; } else { dp[i][j] = dp[i + 1 ][j - 1 ] + 2 ; } } else { dp[i][j] = Math.max(dp[i + 1 ][j], dp[i][j - 1 ]); } maxLen = Math.max(maxLen, dp[i][j]); } } return maxLen; } } |
No comments:
Post a Comment