Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Ensure that numbers within the set are sorted in ascending order.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
A very classic back tracking problem.
Code (Java):
public class Solution { public List<List<Integer>> combinationSum3(int k, int n) { List<List<Integer>> result = new ArrayList<List<Integer>>(); if (k <= 0 || n <= 0) { return result; } List<Integer> curr = new ArrayList<Integer>(); combinationSum3Helper(1, n, 0, k, 0, curr, result); return result; } private void combinationSum3Helper(int start, int n, int count, int k, int curSum, List<Integer> curr, List<List<Integer>> result) { if (count > k) { return; } if (curSum == n && count == k) { result.add(new ArrayList<Integer>(curr)); return; } for (int i = start; i <= 9; i++) { if (curSum + i > n) { break; } curr.add(i); combinationSum3Helper(i + 1, n, count + 1, k, curSum + i, curr, result); curr.remove(curr.size() - 1); } } }
No comments:
Post a Comment