Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Ensure that numbers within the set are sorted in ascending order.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
A very classic back tracking problem.
Code (Java):
public class Solution {
public List<List<Integer>> combinationSum3(int k, int n) {
List<List<Integer>> result = new ArrayList<List<Integer>>();
if (k <= 0 || n <= 0) {
return result;
}
List<Integer> curr = new ArrayList<Integer>();
combinationSum3Helper(1, n, 0, k, 0, curr, result);
return result;
}
private void combinationSum3Helper(int start, int n, int count, int k, int curSum, List<Integer> curr,
List<List<Integer>> result) {
if (count > k) {
return;
}
if (curSum == n && count == k) {
result.add(new ArrayList<Integer>(curr));
return;
}
for (int i = start; i <= 9; i++) {
if (curSum + i > n) {
break;
}
curr.add(i);
combinationSum3Helper(i + 1, n, count + 1, k, curSum + i, curr, result);
curr.remove(curr.size() - 1);
}
}
}
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