Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
Code (Java):
class Solution {
public int firstUniqChar(String s) {
if (s == null || s.length() == 0) {
return -1;
}
int[] counts = new int[26];
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
counts[c - 'a']++;
}
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
if (counts[c - 'a'] == 1) {
return i;
}
}
return -1;
}
}
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