Given an array
A
of integers, for each integer A[i]
we may choose any x
with -K <= x <= K
, and add x
to A[i]
.
After this process, we have some array
B
.
Return the smallest possible difference between the maximum value of
B
and the minimum value of B
.
Example 1:
Input: A = [1], K = 0 Output: 0 Explanation: B = [1]
Example 2:
Input: A = [0,10], K = 2 Output: 6 Explanation: B = [2,8]
Example 3:
Input: A = [1,3,6], K = 3 Output: 0 Explanation: B = [3,3,3] or B = [4,4,4]
Note:
1 <= A.length <= 10000
0 <= A[i] <= 10000
0 <= K <= 10000
Code (Java):
class Solution { public int smallestRangeI(int[] A, int K) { if (A == null || A.length < 2) { return 0; } Arrays.sort(A); int ans = 0; if (A[0] + K >= A[A.length - 1] - K) { return 0; } else { return A[A.length - 1] - K - A[0] - K; } } }
No comments:
Post a Comment