Given an array
A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i].
After this process, we have some array
B.
Return the smallest possible difference between the maximum value of
B and the minimum value of B.
Example 1:
Input: A = [1], K = 0 Output: 0 Explanation: B = [1]
Example 2:
Input: A = [0,10], K = 2 Output: 6 Explanation: B = [2,8]
Example 3:
Input: A = [1,3,6], K = 3 Output: 0 Explanation: B = [3,3,3] or B = [4,4,4]
Note:
1 <= A.length <= 100000 <= A[i] <= 100000 <= K <= 10000
Code (Java):
class Solution {
public int smallestRangeI(int[] A, int K) {
if (A == null || A.length < 2) {
return 0;
}
Arrays.sort(A);
int ans = 0;
if (A[0] + K >= A[A.length - 1] - K) {
return 0;
} else {
return A[A.length - 1] - K - A[0] - K;
}
}
}
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