Given a
undirected graph, a node and a target, return the nearest node to given node which value of it is target, return NULL if you can't find.
There is a
mapping store the nodes' values in the given parameters.Example
Example 1:
Input:
{1,2,3,4#2,1,3#3,1#4,1,5#5,4}
[3,4,5,50,50]
1
50
Output:
4
Explanation:
2------3 5
\ | |
\ | |
\ | |
\ | |
1 --4
Give a node 1, target is 50
there a hash named values which is [3,4,10,50,50], represent:
Value of node 1 is 3
Value of node 2 is 4
Value of node 3 is 10
Value of node 4 is 50
Value of node 5 is 50
Return node 4
Example 2:
Input:
{1,2#2,1}
[0,1]
1
1
Output:
2
Notice
It's guaranteed there is only one available solution
Code (Java):/**
* Definition for graph node.
* class UndirectedGraphNode {
* int label;
* ArrayList<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) {
* label = x; neighbors = new ArrayList<UndirectedGraphNode>();
* }
* };
*/
public class Solution {
/*
* @param graph: a list of Undirected graph node
* @param values: a hash mapping, <UndirectedGraphNode, (int)value>
* @param node: an Undirected graph node
* @param target: An integer
* @return: a node
*/
public UndirectedGraphNode searchNode(ArrayList<UndirectedGraphNode> graph,
Map<UndirectedGraphNode, Integer> values,
UndirectedGraphNode node,
int target) {
// BFS
//
Queue<UndirectedGraphNode> queue = new LinkedList<>();
Set<UndirectedGraphNode> visited = new HashSet<>();
// pre-process the graph
//
Map<UndirectedGraphNode, List<UndirectedGraphNode>> adjList = new HashMap<>();
for (UndirectedGraphNode e : graph) {
adjList.put(e, e.neighbors);
}
queue.offer(node);
visited.add(node);
while (!queue.isEmpty()) {
UndirectedGraphNode curNode = queue.poll();
if (values.get(curNode) == target) {
return curNode;
}
for (UndirectedGraphNode neighbor : adjList.get(curNode)) {
if (!visited.contains(neighbor)) {
queue.offer(neighbor);
visited.add(neighbor);
}
}
}
return null;
}
}
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