Given a
undirected graph
, a node
and a target
, return the nearest node to given node which value of it is target, return NULL
if you can't find.
There is a
mapping
store the nodes' values in the given parameters.Example
Example 1:
Input:
{1,2,3,4#2,1,3#3,1#4,1,5#5,4}
[3,4,5,50,50]
1
50
Output:
4
Explanation:
2------3 5
\ | |
\ | |
\ | |
\ | |
1 --4
Give a node 1, target is 50
there a hash named values which is [3,4,10,50,50], represent:
Value of node 1 is 3
Value of node 2 is 4
Value of node 3 is 10
Value of node 4 is 50
Value of node 5 is 50
Return node 4
Example 2:
Input:
{1,2#2,1}
[0,1]
1
1
Output:
2
Notice
It's guaranteed there is only one available solution
Code (Java):/** * Definition for graph node. * class UndirectedGraphNode { * int label; * ArrayList<UndirectedGraphNode> neighbors; * UndirectedGraphNode(int x) { * label = x; neighbors = new ArrayList<UndirectedGraphNode>(); * } * }; */ public class Solution { /* * @param graph: a list of Undirected graph node * @param values: a hash mapping, <UndirectedGraphNode, (int)value> * @param node: an Undirected graph node * @param target: An integer * @return: a node */ public UndirectedGraphNode searchNode(ArrayList<UndirectedGraphNode> graph, Map<UndirectedGraphNode, Integer> values, UndirectedGraphNode node, int target) { // BFS // Queue<UndirectedGraphNode> queue = new LinkedList<>(); Set<UndirectedGraphNode> visited = new HashSet<>(); // pre-process the graph // Map<UndirectedGraphNode, List<UndirectedGraphNode>> adjList = new HashMap<>(); for (UndirectedGraphNode e : graph) { adjList.put(e, e.neighbors); } queue.offer(node); visited.add(node); while (!queue.isEmpty()) { UndirectedGraphNode curNode = queue.poll(); if (values.get(curNode) == target) { return curNode; } for (UndirectedGraphNode neighbor : adjList.get(curNode)) { if (!visited.contains(neighbor)) { queue.offer(neighbor); visited.add(neighbor); } } } return null; } }
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