Given a non-empty string
s
, you may delete at most one character. Judge whether you can make it a palindrome.
Example 1:
Input: "aba" Output: True
Example 2:
Input: "abca" Output: True Explanation: You could delete the character 'c'.
Note:
- The string will only contain lowercase characters a-z. The maximum length of the string is 50000.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 | class Solution { public boolean validPalindrome(String s) { if (s == null || s.length() < 2 ) { return true ; } int left = 0 ; int right = s.length() - 1 ; while ( left < right && s.charAt(left) == s.charAt(right)) { left++; right--; } if (left >= right) { return true ; } if (isPalin(s, left + 1 , right) || isPalin(s, left, right - 1 )) { return true ; } return false ; } private boolean isPalin(String s, int left, int right) { while (left < right) { if (s.charAt(left) == s.charAt(right)) { left++; right--; } else { break ; } } return left >= right; } } |
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