Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
Code (Java):
class Solution {
    public int firstUniqChar(String s) {
        if (s == null || s.length() == 0) {
            return -1;
        }
        int[] counts = new int[26];
        for (int i = 0; i < s.length(); i++) {
            char c = s.charAt(i);
            counts[c - 'a']++;
        }
        for (int i = 0; i < s.length(); i++) {
            char c = s.charAt(i);
            if (counts[c - 'a'] == 1) {
                return i;
            }
        }
        return -1;
    }
}
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